Find the zero of the polynomial x^2-3and relationship between the zero and the cofficent
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Hiii friend,
P(X) = X²-3
=>(X)² - (✓3)²
=> (X+✓3) (X-✓3) = 0
=>(X+✓3) = 0 OR (X-✓3) = 0
=> X = -✓3 OR X = ✓3
-✓3 and ✓3 are the two zeros of the polynomial X²-3
Let Alpha = -✓3 and beta = ✓3
Relationship between the zeros and tne the coefficient.
Sum of Zeros = (Alpha + Beta ) = (-✓3+✓3) = 0 = Coefficient of X/Coefficient of X².
Product of zeros = (Alpha × Beta) = (-✓3×✓3) = 3/1 = Constant term/Coefficient of X².
HOPE IT WILL HELP YOU...... :-)
P(X) = X²-3
=>(X)² - (✓3)²
=> (X+✓3) (X-✓3) = 0
=>(X+✓3) = 0 OR (X-✓3) = 0
=> X = -✓3 OR X = ✓3
-✓3 and ✓3 are the two zeros of the polynomial X²-3
Let Alpha = -✓3 and beta = ✓3
Relationship between the zeros and tne the coefficient.
Sum of Zeros = (Alpha + Beta ) = (-✓3+✓3) = 0 = Coefficient of X/Coefficient of X².
Product of zeros = (Alpha × Beta) = (-✓3×✓3) = 3/1 = Constant term/Coefficient of X².
HOPE IT WILL HELP YOU...... :-)
poojakushwaha:
Thank you
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