Find the zero's of
| P(x)= x²-7x +12
Answers
Answered by
5
Step-by-step explanation:
x ^2 -7x+12
x^2-4x-3x+12
x(x-4) 3(x-4)
(x-4) (x+3)
now x-4=0
x= 4
in second bracket x+3= 0
x= -3
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Answered by
88
Answer:
Step-by-step explanation:
□ P(x)= x²-7x +12
○To find zeroes of this eqn:
☆Middle term spliting:
☆Quadratic formula:
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