Question

find the zerod of the polynomial (x-2)^2+4​

Answer 1

Step-by-step explanation:

( x - 2 )^2 + 4

= x^2 + 2^2 - 2 × x × 2 ( a + b )^2

= x^2 + 4 - 4x + 4

= x^2 - 4x + 8

=

Answer 2

Step-by-step explanation:

Hi Friend !!!!

Here is ur answer !!!

(x-2)²+4

= x²+2²-4x+4

= x²-4x+8

discriminant, Δ= b²-4ac

=(-4)²-4(1)(8)

= 16-32

= -16

so, this polynomial has no real zeroes

Hope it helps u : )