find the zeroes od the plynomial 4x^2-7
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Answer:
4x²-7=0
4x²=7
x²=7/4
x=√7/4
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Let f(x) = 4x2 - 7
4x2 - 7 = 0
(2x)2 - (√7)2 =
Using a2 - b2 = (a - b)(a + b), we have
(2x - √7)(2x + √7) = 0
2x - √7 = 0 or 2x + √7 = 0
2x = √7 or 2x = -√7
x = √7/2 or x = -√7/2
α + β = √7/2 + (-√7/2) = 0 = 0/4 = -b/a
αβ = √7/2*-√7/2 = -7/4 = c/a
So, α + β = -b/a and αβ = c/a
HOPE , IT HELPS ... ✌
4x2 - 7 = 0
(2x)2 - (√7)2 =
Using a2 - b2 = (a - b)(a + b), we have
(2x - √7)(2x + √7) = 0
2x - √7 = 0 or 2x + √7 = 0
2x = √7 or 2x = -√7
x = √7/2 or x = -√7/2
α + β = √7/2 + (-√7/2) = 0 = 0/4 = -b/a
αβ = √7/2*-√7/2 = -7/4 = c/a
So, α + β = -b/a and αβ = c/a
HOPE , IT HELPS ... ✌
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