Find the zeroes of 3x²-5x-2 and verify the relationship between the zeroes and the coefficients. If Alpha=© and Beta=℅
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Answered by
31
zeros will be 2 and -1/3
sum of Zeroes = -b/a =5/3
product of Zeroes = c/a = 2/3
sum of Zeroes = -b/a =5/3
product of Zeroes = c/a = 2/3
AyushKhurana:
Could you elaborate please
Answered by
106
Given polynomial,
3x²-5x-2 = 0
3x²-6x+x-2=0
3x(x-2)+1(x-2)=0
(x-2)(3x+1)=0
x-2=0 ; 3x+1=0
x=2 ; x=-1/3
Therefore, the zeroes of the polynomial are 2 and -1/3
Let α(alpha) =2
β(beta) =-1/3
Sum of zeroes = α+β=2+(-1/3)
=2-1/3
=(6-1)/3
=5/3=-(-5)/3
=-(x coefficient)/x² coefficient
Product of zeroes=αβ=2(-1/3)=-2/3
=constant/x² coefficient
Hope it helps
3x²-5x-2 = 0
3x²-6x+x-2=0
3x(x-2)+1(x-2)=0
(x-2)(3x+1)=0
x-2=0 ; 3x+1=0
x=2 ; x=-1/3
Therefore, the zeroes of the polynomial are 2 and -1/3
Let α(alpha) =2
β(beta) =-1/3
Sum of zeroes = α+β=2+(-1/3)
=2-1/3
=(6-1)/3
=5/3=-(-5)/3
=-(x coefficient)/x² coefficient
Product of zeroes=αβ=2(-1/3)=-2/3
=constant/x² coefficient
Hope it helps
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