find the zeroes of 6x2 -5x +1
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Given polynomial, 6x² - 5x + 1
6x²-5x+1 = 0
6x²-2x-3x+1 = 0
2x(3x-1)-1(3x-1) = 0
(3x-1)(2x-1) = 0
x = ⅓ and x = ½ are the zeroes
6x²-5x+1 = 0
6x²-2x-3x+1 = 0
2x(3x-1)-1(3x-1) = 0
(3x-1)(2x-1) = 0
x = ⅓ and x = ½ are the zeroes
Answered by
4
Hi !
6x² - 5x + 1 = 0
splitting the middle term :-
6x² - 2x- 3x + 1 = 0
2x (3x-1) - 1(3x-1) = 0
(3x-1) (2x-1) = 0
x = 1/3
x = 1/2
1/2 and 1/3 are the zeros !!
6x² - 5x + 1 = 0
splitting the middle term :-
6x² - 2x- 3x + 1 = 0
2x (3x-1) - 1(3x-1) = 0
(3x-1) (2x-1) = 0
x = 1/3
x = 1/2
1/2 and 1/3 are the zeros !!
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