Question

find the zeroes of f[x] =x^2 - [ under root 2 + 1 ] x +under root 2

Answer 1

Heeeeeyaaaa

$f(x) = {x}^{2} - \sqrt{2} x - x + \sqrt{2}$

$f(x) = (x - \sqrt{2} )(x - 1)$

Hence, whenever
$f(x) = 0$

We have either of :
$(x - \sqrt{2} ) = 0$
Or
$(x - 1) = 0$


Hence, the two zeroes are :
$x = \sqrt{2} \: or \: 1$