Math, asked by tidtidtidufxugdihfih, 4 months ago

Find the zeroes of quadratic polynomial  {x}^{2} + 7x + 10and find relationship between zeroes and co efficients.​

Answers

Answered by MissLuxuRiant
0

\huge{\star{\orange{\boxed{\pink{\boxed{\underline{\mathbb{\red{ANSWER:-}}}}}}}}}

\longrightarrow \sf{x}^{2} + 7x + 10x

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\sf{by\:splitting\:the\:middle\:term}

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\longrightarrow \sf{{x}^{2} + 5x + 2x + 10}

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\longrightarrow \sf{x(x+5)+2(x+5)}

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\longrightarrow \sf{(x+2)(x+5)}

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\sf{x+2=0}

\sf{x=-2}

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\sf{x+5=0}

\sf{x=-5}

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\sf{Sum\:of\:zeroes=-2+(-5)}

\sf\huge\frac{ - (coeff.of \: x)}{coeff.of {x}^{2}}

\sf{-2-5}−2−5 =⠀\sf\frac{-7}{1}

\sf{-7}

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\sf{Product\:of\:zeroes=(-2) ×(-5)=}

\sf\huge\frac{constant \: term}{coeff. \: of \: {x}^{2} }

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\longrightarrow \sf\Large{10=10}

Answered by ItzDazzingBoy
0

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