Question

Find the zeroes of the given polynomials.
(i) P(x) 3x
(ii) p(x) = x2 + 5x + 6
(iv) p(x) -16
(iii) p(x) = (x+2)(x+3)​

Answer 1

Answer:

question 2

first we apply the polynomial in the form of ax2+bx+c

so we can find that

a=1, b=5 ,and c =6

then multiply a by c

1×6=6

by middle term split method

we split the 5x in the form of that in which whenwe add them they gives 5x and when we multiply them they gives 6 so we find the lcm of 6. the factor s are.

3 ,and 2 so we put 3x and 2x at the place of 5x so the eq form x2 +3x+2x+6

then we factorise itit gives (x+2)(x+3)so that the zeroes is -2,-3