Find the zeroes of the given polynomials.
p(x)=x^2+5x+6
p(x)=(x+2)(x+3)
p(x)=x^4-16
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Answer:
(i) = -2,-3 , (ii) = -2,-3 ,(iii) = 2
Step-by-step explanation:
(i) x^2 +2x+3x+6 =0
=> x( x+2) +3(x+2) =0
=> (x+3) (x+2) = 0
=> x= -3,-2
(ii) (x+2) (x+3) = 0
=> x= -2,-3
(iii) x^4 = 16
=> 2^4 = 16
=> x= 2 . This is the required answer.
Thank you.
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