find the zeroes of the POLYMNOAL p(x)=x²-3
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Answer:
p(x) = x²-3
zeroes = x = √3 and -√3
Answered by
0
Answer:
x = √3, - √3
Step-by-step explanation:
Substituting p(x) = 0 to get the zeroes of the given polynomial,
x^2 - 3 = 0
(x+√3)(x-√3) = 0
Therefore, x = -√3 and x = √3.
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