Find the zeroes of the polynomial 2x^2-10 and verify the relationship between the zeroes and the coefficient ?
Answers
Answered by
32
2x^2 - 10
2x^2 = 10
x^2 = 10/2
x^2 = 5
x = plus minus under root 5
Zeros
x =+ root 5. x = - root 5
Sum = -b/a = -0/2 = 0
Product = c/a = -10/2 = -5
Verification :
Sum = alpha + beta = root5 + (-root5)
= root5 - root5 = 0
Product = alpha.beta = root5.(-root5)
= -5
Hence Verified !
2x^2 = 10
x^2 = 10/2
x^2 = 5
x = plus minus under root 5
Zeros
x =+ root 5. x = - root 5
Sum = -b/a = -0/2 = 0
Product = c/a = -10/2 = -5
Verification :
Sum = alpha + beta = root5 + (-root5)
= root5 - root5 = 0
Product = alpha.beta = root5.(-root5)
= -5
Hence Verified !
Answered by
4
Answer:
above answer is correct
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