Question

Find the zeroes of the polynomial √3y2 + 10y + 7√3 and verify the relationship between the zeroes and the coefficients

Answer 1

Answer:

The zeroes are -$\sqrt{3}$ OR -7/$\sqrt{3}$

Step-by-step explanation:

Relations between coefficients and zeroes: $\frac{-b \ +OR- \sqrt{b^2 - 4ac} }{2a}$

This is called The Quadratic Formula.

It gives 2 solutions.

Applying this to $\sqrt{3}y^2 + 10y + 7\sqrt{3}$:

a = $\sqrt{3}$

b = 10

c = $7\sqrt{3}$

Applying the formula,

$\frac{-10 + \sqrt{100 - 4*21} }{2\sqrt{3} }$ OR $\frac{-10 - \sqrt{100 - 4*21} }{2\sqrt{3}}$

=> $\frac{-10 + \sqrt{100 - 84} }{2\sqrt{3}}$ OR $\frac{-10 - \sqrt{100 - 84} }{2\sqrt{3}}$

=> $\frac{-10 + \sqrt{16} }{2\sqrt{3}} OR \frac{-10- \sqrt{16}}{2\sqrt{3}}$

=> -6/2$\sqrt{3}$ OR -14/$2\sqrt{3}$

=> $\sqrt{3}$ OR 7/$\sqrt{3}$

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