Question

find the zeroes of the polynomial 5t2+12t+7
and verify the relationship between the zeroes and the coefficients of the polynomial

Answer 1

5t²+12t+7
5t²+5t+7t+7
5t(t+1)+7(t+1)
t=-1,-7/5
α+β=-b/a
-1+-7/5=-12/5
-12/5=-12/5
αβ=c/a
-1*-7/5=7/5
7/5=7/5