Question

Find the zeroes of the polynomial p(x)=x cube-27

Answer 1

Answer:

Let α,β be the other zeros of the given polynomial x  

3

+ax  

2

+bx  

2

+c

Sum of the zeros =  

coefficient of x  

3

 

−coefficient of x  

2

 

​  

 

⇒−1+α+β=  

1

−a

​  

=−a

⇒α+β=−a+1 (i)

Again,

(−1)α+αβ+(−1)β=  

coefficient of x  

3

 

−coefficient of x

​  

 

⇒−α+αβ−β=  

1

b

​  

 

=αβ=b+α+β    

(α+β=−a+1 , from (i))

=b−a+1  

Step-by-step explanation: