Question

Find the zeroes of the polynomial x^2-3

Answer 1

Hii...☺

Here is your answer....☺

================================

✒ x² - 3

=> (x)² - (√3)²

By using a² - b² = ( a + b )(a -b) we get,

=> ( x + √3) ( x - √3) = 0

=> x = -√3 or √3

===============================

Hence, zeroes of the polynomial are -√3 and √3.

Thanks...☺