Question

find the zeroes of the quadratic polynomial 3x2 - x -4 and verify the relation between the zeroes and the coefficient of the polynomial​

Answer 1

Answer:

p (x) = 3x² - x - 4

» 3x² - x - 4 = 0

» 3x² - 4x + 3x - 4 = 0

» x (3x - 4) + (3x - 4) = 0

» (3x - 4) (x + 1) = 0

» x = 4/3 or x = - 1

Answer 2

Answer:

x= 4/3 Nd x= -1

Step-by-step explanation:

3x^2-x-4=0

By using splitting method

3x^2+3x-4x-4=0

3x(x+1)-4(x+1)=0

(3x-4) (x+1)=0

zeros are

3x-4=0. nd x+1=0

3x= 4. x= -1

x=4/3