Question

find the zeroes of the quadratic polynomial and verify the relationship between the zeroes and the coefficient : 8y^2-3y​

Answer 1

Let m and n be the zeroes.

p(x) = 8y² - 3y

8y² - 3y = 0

y (8y-3) =0

y = 0 or y = 3/8

Let m=0 and n= 3/8

Now,

m + n = - b/a

0 + 3/8 = (-3/8)

3/8 = 3/8

Also,

mn = c/a

0× 3/8= 0 /8

0 =0

Hence the relation between zeroes and coefficient is verified.

Answer 2

Answer:

Zeros of quadratic polynomial are 0 and 3/8.

Step-by-step explanation:

Let p and q be the zeroes of given quadratic polynomial.

A = 8y² - 3y

So quadratic equation will be

8y² - 3y = 0........(i)

y (8y - 3) =0

If (8y - 3) = 0

y = 3/8

So y = 0 and y = 3/8

And p = 0 and q = 3/8

Comparing equation (i) with ay² + by + c = 0

a = 8, b = -3, c = 0

∵Sum of roots = -b/a

p + q = - b/a

0 + (3/8) = -(-3)/8

3/8 = 3/8

∵L.H.S = R.H.S

So relationship verified.

Similarly,

∵Multiplication of roots = c/a

p × q = c/a

0 × (3/8) = 0/8

0 = 0

∵L.H.S = R.H.S

So relationship verified.

Hence the relation between zeroes and coefficient is verified.

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