find the zeroes of the quadratic polynomial x ^2-20x+91 and verify relationship between the zeros and and the coefficients
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Answered by
54
Hii friend,
P(X) = X²-20X+91
=> X²-13X-7X+91
=> X(X-13) -7(X-13)
=> (X-13) (X-7)
=> (X-13) = 0. OR (X-7) = 0
=> X = 13. OR X = 7
Hence,
13 and 7 are the two zeros of the quadratic polynomial X²-20X+91.
Let Alpha = 13 and Beta = 7.
Sum of zeros = (Alpha + Beta) = (13+7) = 20/1 = Coefficient of X/Coefficient of X².
Product of zeros = (Alpha × Beta) = (13×7) = 91/1 = Constant term/Coefficient of X²..
HOPE IT WILL HELP YOU.... :-)
P(X) = X²-20X+91
=> X²-13X-7X+91
=> X(X-13) -7(X-13)
=> (X-13) (X-7)
=> (X-13) = 0. OR (X-7) = 0
=> X = 13. OR X = 7
Hence,
13 and 7 are the two zeros of the quadratic polynomial X²-20X+91.
Let Alpha = 13 and Beta = 7.
Sum of zeros = (Alpha + Beta) = (13+7) = 20/1 = Coefficient of X/Coefficient of X².
Product of zeros = (Alpha × Beta) = (13×7) = 91/1 = Constant term/Coefficient of X²..
HOPE IT WILL HELP YOU.... :-)
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