Find the zeroes of the quadratic polynomial x2 + 7x + 10, and verify the relationship between the zeroes and the coefficients.
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Answered by
14
x2 + 7x + 10 = 0
or, x2 +2x+5x +10 = 0
or, (x+2)(x+5) = 0
or, x = -2,-5
So, x2 + 7x + 10 = -2*-2 + 7*-2 + 10 = 4+10-14 = 0
Again, x2 + 7x + 10 = -5*-5 + 7*-5 +10 = 25+10-35 = 0
or, x2 +2x+5x +10 = 0
or, (x+2)(x+5) = 0
or, x = -2,-5
So, x2 + 7x + 10 = -2*-2 + 7*-2 + 10 = 4+10-14 = 0
Again, x2 + 7x + 10 = -5*-5 + 7*-5 +10 = 25+10-35 = 0
Answered by
3
Answer:
Step-by-step explanation:
x2 + 7x + 10 = 0
or, x2 +2x+5x +10 = 0
or, (x+2)(x+5) = 0
or, x = -2,-5
So, x2 + 7x + 10 = -2*-2 + 7*-2 + 10 = 4+10-14 = 0
Again, x2 + 7x + 10 = -5*-5 + 7*-5 +10 = 25+10-35 = 0
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