Question

find the zeroes of the quadratic
polynomial x²+7x+10, and verify
the relationship between the
zeroes and the coefficients.​

Answer 1

Answer:

x²+7x+10=0

x²+2x+5x+10=0

x(x+2)+5(x+2)=0

(x+2)(x+5) = 0

x+2 = 0 ; x = -2

x+5 = 0 ; x = -5

Relationship between the zeroes and coefficients :-

Sum of zeroes = -2+(-5) = -2-5

= -7/1 = -x coefficient /x² coefficient

Product of zeroes = (-2)(-5)

= 10/1 = constant/x² coefficient

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Answer 2

$\huge{\underline{\mathfrak {\purple{Answer}}}}$

x²+7x+10

x²+(5x +2x) +10

x²+ 5x + 2x + 10

x(x + 5) + 2(x + 5)

(x + 5) ( x + 2)

> x + 5 = 0

> x = -5

x + 2 =0

x = -2

The Answer Will be -5 , -2