Question

Find the zeroes of the quadratic polynomial x2-7x+12 and verify the relation between the two zeroes and its coefficients?

Answer 1

Step-by-step explanation:

x²-7x+12

x²-4x-3x+12

x(x-4)-3(x-4)

(x-4)(x-3)

x=4 x=3

{Sum of zeroes = α+β = 4+3 =7

Product of zeroes = α*β = 4*3=12} - eq 1

{Sum of zeroes = -b/a = -(-7)/1 = 7

Product of zeroes = c/a = 12/1 = 12} - eq 2

From eq 1 and eq 2, the relationship between zeroes is verified.