Question

find the zeroes of thequadratic polynomial x square - 2 x minus 8 and verify the relationship between the zeros and the coefficient​

Answer 1

Answer: x=4,-2

Step-by-step explanation:

x^2-2x-8=0

x^2-4x+2x-8=0

x(x-4)+2(x-4)=0

(x+2)(x-4)=0

x=4,-2

relation between the zeros and the coefficient

we know,

sum of zeros=-(coefficient of x)/(coefficient of x^2)

i.e 4+(-2)=-(-2/1)

    2 = 2

product of zeros=(coefficient of constant)/(coefficient of x^2)

i.e 4*(-2)=(-8/1)

       -8 = -8

Hence proved..