Find the zeroes of x square -3
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Solution :
Let the given polynomial be p(x)
Then, p(x) = x² - 3
To find zeros of p(x)
We need to put p(x) = 0
→ x² - 3 = 0
→ x² - (√3)² = 0
→ (x + √3) (x - √3) = 0
[ Using Identity, a² - b² = (a + b) ( a - b) ]
→ x + √3 = 0 or x - √3 = 0
→ x = - √3 or x = √3
Hence,
Zeros of x² - 3 are √3 and - √3
Let the given polynomial be p(x)
Then, p(x) = x² - 3
To find zeros of p(x)
We need to put p(x) = 0
→ x² - 3 = 0
→ x² - (√3)² = 0
→ (x + √3) (x - √3) = 0
[ Using Identity, a² - b² = (a + b) ( a - b) ]
→ x + √3 = 0 or x - √3 = 0
→ x = - √3 or x = √3
Hence,
Zeros of x² - 3 are √3 and - √3
amaya1257:
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