Question

find the zeros of 3✓2x^2+13x+6✓2

Answer 1

3√2 x² + 13 x + 6√2
= 3√2 x² + 9x + 4x + 6√2
= 3x(√2 x + 3) + 2√2(√2x + 3)
= (√2x + 3)(3x + 2√2)

Zeroes of the polynomial:
(3x + 2√2) = 0
⇒ x = 2√2/3
(√2x + 3) = 0
⇒ x = -3/√2
Sum of the roots = 2√2/3 -3/√2 = -13/3√2
Product of the roots = 2√2/3 × 3/√2 = 2

Sum of the roots = -b/a = -13/3√2
Product of the roots = c/a = 6√2 / 3√2 = 2.

Answer 2

To find Zeroes, Equate the given polynomial with 0.