find the zeros of polynomial 9x^2+15x+4
Attachments:
Answers
Answered by
0
Answer:
Answer
We have
9x
2
−15x+6=0
⇒x
2
−
9
15
x+
9
6
=0 (Dividing throughout by 9)
⇒x
2
−
3
5
x+
3
2
=0⇒x
2
−
3
5
x=−
3
2
(Shifting the constant term on RHS)
⇒x
2
−2(
6
5
)x+(
6
5
)
2
=(
6
5
)
2
−
3
2
(Adding square of half of coefficient of x on both sides)
⇒(x−
6
5
)
2
=
36
25
−
3
2
⇒(x−
6
5
)
2
=
36
1
⇒x−
6
5
=±
6
1
(Taking square root on both sides)
⇒x=
6
5
+
6
1
=1orx=
6
5
−
6
1
=
3
2
⇒x=1orx=
3
2
Hence the roots of the equation are 1 and
3
2
Similar questions