Question

Find the zeros of polynomial (x-2)^2-4

Answer 1

$(x - 2) ^{2} - 4 = 0 \\ {x}^{2} + 4 - 4x - 4 = 0 \\ {x}^{2} - 4x = 0 \\ x(x - 4) = 0 \\ x = 0 \: \:or \: \: \: \: \: x - 4 = 0 \: \: \: => x = 4$

Answer 2

Answer:

(x-2)^2=x^2+4-4x

=x^2+4-4x-4

=x^2-4x

roots of the equation is -b + or -√b ^2-4ac/2a

a=1,b=(-4),c=0

4 + or- √16-0/2(1)

4 + or -4/2

=4+4/2(or)4-4/2

=4 (or)0

the roots of the equation are 4,0

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