Question

find the zeros of polynomial (x)=x2-2x-8 and verify the relationship between zeros and it's cofficient​

Answer 1

x²-2x-8 = 0

=> x²-(4-2)x-8 = 0

=> x²-4x+2x-8 = 0

=> x(x-4) +2(x-4) = 0

=> (x-4) (x+2) = 0

So, x = 4 or, x = -2.

Hence, the zeroes are 4 and -2.

For the next question, what kind of coefficient you're talking about is unclear to me.

Answer 2

ye..................