Find the zeros of quadratic polynomolial,3x^-x-4 and verify a relationship b/w zeros and it's coefficients
Answers
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
It is given that
3x²-x-4=0
4X3=12
4-3=1
3x²-(4-3)x-4=0
3x²-4x+3x-4=0
3x²+3x-4x-4=0
3x(x+1)-4(x+1)=0
(3x-4)(x+1)=0
If 3x-4=0 If x+1=0
then x=4/3 then x=-1
Sum of zeros = 4/3-1
=4-3/3
=1/3 -------------(i)
Product of zeros = 4/3X(-1)
=-4/3 --------------(ii)
By question
3x²-x-4=0
Comparing with ax²+bx+c=0
then a=3 , b= -1 , c= -4
Sum of zeros = -b/a
= -(-1/3)
= 1/3 ----------------(iii)
Product of zeros = c/a
=-4/3 -----------------(iv)
By (i) and (iii) Sum of zeros is verified.
By (ii) and (iv) Product of zeros is verified.
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