Question

find the zeros of the following polynomial 2x²+3x-90​

Answer 1

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given:   (2x2 +  3x) -  90  = 0

Solution:

Simplifying

2x2 + 3x + -90 = 0

Reorder the terms:

-90 + 3x + 2x2 = 0

Solving

-90 + 3x + 2x2 = 0

Solving for variable 'x'.

Factor a trinomial.

(-15 + -2x)(6 + -1x) = 0

Answer 2

Answer:

-30/4 or 6

Step-by-step explanation:

X = -b ± (√b²-4ac)/2a

= -3 ± (√9+720)/4

= -3 ± 27/4

X = -3 + 27 / 4 = 24/4 = 6

or

X = -3 - 27/4 = -30/4

I hope it helps...