Question

Find the zeros of the given polynomial and verify the relation between the zeros and the coefficients x^2-2x-8

Answer 1

Answer:

Zeroes of p(x) are -2 and 4

Step-by-step explanation:

Here,

f(x) = x^2 -2x-8

= x^2 - 4x +2x -8

= x(x-4) + 2(x-4)

= (x+2)(x-4)

Now, f(x) = 0

=> (x+2)(x-4) = 0

=> x = -2 , x = 4

Hence, Zeroes of the polynomial p(x) are -2 and 4.

Now,

Sum of the zeroes = (-2+4)

= 2

= 2/1

= -(coefficient of x) / (coefficient of x^2)

Now, Product of the zeroes = (-2×4) = -8/1

= constant term/ coefficient of x^2.

Hope it helps.