Question

find the zeros of the polynomial 4x^2-12x+9

Answer 1

Here is ur answer...
$4 { x }^{2} - 12x + 9 = 0 \\ = 4 {x}^{2} - 6x - 6x + 9 = 0 \\ = 2x(2x - 3) - 3(2x - 3) \\ = (2x - 3)(2x - 3) = 0 \\ so \: \: \: x = 3 \div 2 \: or \: \: 3 \div 2$

Answer 2

Zeros of polynomial are 3/2 and 3/2

Solution:

Given that, we have to find zeros of polynomial

Given polynomial is:

$4x^2 -12x+9$

Find the zeros:

$4x^2 -12x+9 = 0$

Split the middle term

$4x^2-6x-6x+9 = 0$

Break the expression intp groups

$(4x^2-6x)-(6x-9) = 0$

Factor 2x from first group and 3 from second group

$2x(2x - 3) - 3(2x - 3) = 0$

Factor out 2x - 3

$(2x-3)(2x-3) = 0\\\\2x - 3 = 0\\\\x = \frac{3}{2}\\\\2x - 3 = 0\\\\x = \frac{3}{2}$

Thus zeros of polynomial are 3/2 and 3/2

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