Question

find the zeros of the polynomial x square - 3 and verify the relationship between the zeros and the coefficients
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Answer 1

Answer:

Hey mate

Step-by-step explanation:

x2-3

x2=3

x= root 3

Zeroes make the result come zero and is called zero of polynomial

Answer 2

Answer:

x²-3

x²+0x-3

x²+√3x - √3x -3

x(x+√3) -√3(x+√3)

x-√3. x+√3

x = √3. x= -√3

alfha = √3. beta= -√3

Verification:

Sum of zeroes= alfha + beta = √3+(-√3) =0=-0/1=0/1 = -b/a

Product of zeroes = alfha*beta= √3 *-√3 = -3 = -3/1 = c/a