Question

find the zeros of the polynomial x square - 3 and verify the relationship between 0 and the coefficient​

Answer 1

x² - 3

In the form of quadratic equation a = 1, b = 0 and c = -3

x² - 3 = 0

=> x² = 3

=> x = √3 & -√3

Sum of zeroes = √3 + (-√3) = 0

Multiplication of zeroes = √3 × (-√3) = -3

Sum of zeroes = -b/a = 0/1 = 0

Hence verified that sum of zeroes = -b/a

Multiplication of zeroes = c/a = -3/1 = -3

Hence verified that multiplication of zeroes = c/a

hope it helps.

Answer 2

Answer:

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Given polynomial is x

2

−3

Here, a=1,b=0 and c=−3

x

2

−3=(x−

3

)(x−

3

)

So, the value of x

2

−3 is zero when x=

3

or x=−

3

Threrfore , thr zeroes of x

2

−3 are

3

and −

3

.

Now, sum of zeroes =

3

−

3

=0=

1

0

=

a

−b

product of zeroes =(

3

)(−

3

)=−3=

1

−3

=

a

c

Hence verified.