Question

find the zeros of the polynomial x square minus x - 72 and verify the relationship between the zeros and the coefficients​

Answer 1

$\boxed{\textbf{\large{Step-by-step explanation:}}}$

given polynomial is,

x² - x - 72 = 0

→ x² - 9x + 8x - 72 = 0

→ x ( x - 9 ) + 8 ( x - 9 ) = 0

→ ( x + 8 ) ( x - 9 )

→ x = - 8 , x = 9

if we consider the zeros of polynomial are α and β then,

▶the relationship between the zeros and the coefficients is

α x β = c /a and ( α + β )= ( -b / a )

$\boxed{\textbf{\large{alpha = -8}}}$

$\boxed{\textbf{\large{ beta = 9}}}$

→ α + β = -b / a

→ -b / a = -8 + 9

→ -b / a = 1

$\boxed{\textbf{\large{b / a = - 1}}}$

Now,

→ α x B = c / a

→ c / a = - 8 x 9

$\boxed{\textbf{\large{ c / a = - 72}}}$

Answer 2

Answer:

alpha = -8

beta = 9

Step-by-step explanation:

the step by step explanation has been attached by photo

Hope it helps you