find the zeros of the polynomial x2- 3 and verify the relationship between the zeros and the cofficients
Answers
Answered by
663
x²-3=0
x²=3
x=+√3 or -√3
Verification:-
x²-3
=(√3)²-3
=3-3
=0
x²-3
=(-√3)²-3
=3-3
=0
x²=3
x=+√3 or -√3
Verification:-
x²-3
=(√3)²-3
=3-3
=0
x²-3
=(-√3)²-3
=3-3
=0
Answered by
896
x²-3 = 0
x² = 3
x = ±√3
Therefore, the zeroes of the given polynomial are √3 and -√3.
Relationship between the zeroes and coefficients :-
Sum of zeroes = √3+(-√3) = √3-√3
= 0 = -x coefficient/x² coefficient
Product of zeroes = (√3)(-√3)
= -(√3)² = -3/1 = constant/x² coefficient
Hope it helps
x² = 3
x = ±√3
Therefore, the zeroes of the given polynomial are √3 and -√3.
Relationship between the zeroes and coefficients :-
Sum of zeroes = √3+(-√3) = √3-√3
= 0 = -x coefficient/x² coefficient
Product of zeroes = (√3)(-√3)
= -(√3)² = -3/1 = constant/x² coefficient
Hope it helps
Similar questions