if x=2+under root 3 find the value of x cube +1/x cube
Answers
Answered by
1015
x = 2 + √3
1/x = 1/(2 + √3)
= (2 -√3)/(2 +√3)(2 -√3)
= (2 -√3)/(2² -√3²)
= (2 - √3)
hence, x + 1/x = (2+√3)+(2-√3) = 4
x³ + 1/x³ = (x + 1/x)³ -3(x + 1/x)
= (4)³ - 3(4)
= 64 -12
= 52
1/x = 1/(2 + √3)
= (2 -√3)/(2 +√3)(2 -√3)
= (2 -√3)/(2² -√3²)
= (2 - √3)
hence, x + 1/x = (2+√3)+(2-√3) = 4
x³ + 1/x³ = (x + 1/x)³ -3(x + 1/x)
= (4)³ - 3(4)
= 64 -12
= 52
Answered by
577
x = 2+√3
1/x = 1/(2 + √3)
= (2 -√3)/(2 +√3)(2 -√3)
= (2-√3)/(2² -√3²)
= (2-√3)
x+1/x = 2+√3+2-√3
= 4
(x+1/x)³ = x³+1/x³+3(x)(1/x)[x+1/x]
x³+1/x³ = (4)³-3(4)
= 64-12
= 52
Hope it helps
1/x = 1/(2 + √3)
= (2 -√3)/(2 +√3)(2 -√3)
= (2-√3)/(2² -√3²)
= (2-√3)
x+1/x = 2+√3+2-√3
= 4
(x+1/x)³ = x³+1/x³+3(x)(1/x)[x+1/x]
x³+1/x³ = (4)³-3(4)
= 64-12
= 52
Hope it helps
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