Question

Find the zeros of the polynomial
x2 + 7x + 10

Answer 1

Answer:

x²+7x+10=0

x²+2x+5x+10=0

x(x+2)+5(x+2)=0

(x+2)(x+5) = 0

x+2 = 0 ; x = -2

x+5 = 0 ; x = -5

Relationship between the zeroes and coefficients :-

Sum of zeroes = -2+(-5) = -2-5

= -7/1 = -x coefficient /x² coefficient

Product of zeroes = (-2)(-5)

= 10/1 = constant/x² coefficient

Hope it helps

Step-by-step explanation:

Answer 2

Answer:

-2 and -5

Step-by-step explanation:

x^2+ 5x+ 2x+ 10

x(x+5) +2( x+5)

(x+2) (x+5)

Zero of eq ,

when,x+2=0 OR x+5=0

x=-2 OR x= -5