find the zeros of the quadratic polynomial √3x²-8x+4√3
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Answered by
21
hi friend ,
Given quadratic polynomial √3x²-8x+4√3
→√3x²-6x-2x+4√3
→√3x(x-2√3)-2(x-2√3)
→(√3x-2)(x-2√3)
so,the zeros of the given polynomial are 2/√3,2√3
I hope this will help u ;)
♥dhathri123♥
Given quadratic polynomial √3x²-8x+4√3
→√3x²-6x-2x+4√3
→√3x(x-2√3)-2(x-2√3)
→(√3x-2)(x-2√3)
so,the zeros of the given polynomial are 2/√3,2√3
I hope this will help u ;)
♥dhathri123♥
Anonymous:
thq very much my friend
Answered by
8
Hello dearie !
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f(x) = √3x² - 8x + 4√3
= √3x² -6x - 2x + 4√3
= √3x(x-2√3) -2(x-2√3
= (x-2√3) (√3x -2)
= x = +2√3 OR +2/√3
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_____________________________________________________________
f(x) = √3x² - 8x + 4√3
= √3x² -6x - 2x + 4√3
= √3x(x-2√3) -2(x-2√3
= (x-2√3) (√3x -2)
= x = +2√3 OR +2/√3
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