Question

find the zeros of the quadratic polynomial 5x²-4-8x

Answer 1

$Heya$‼


$Given\:polynomial:5x^2-4-8x$

$As\:we\:know,$
$the\:standard:form \:of\:a\:quadratic \:polynomial\:is\:as\:follows:$
$ax^2+bx+c$

$5x^2-4-8x=0$
$5x^2-8x-4=0$
$5x^2-10x+2x-4=0$
$5x(x-2)+2(x-2)=0$
$(5x+2)(x-2)=0$
$(5x+2)=0\:or\:(x-2)=0$

$x=\frac{-2}{5}\:or\:x=2$


Hence, the zeroes of given polynomial are $\frac{-2}{5}$ and $2$.