Question

find the zeros of the quadratic polynomial 6x square - 3 and the relation between the zeros and its coefficient

Answer 1

6x^2-3=0
6x^2=3
x^2=3/6
x^2=1/2
x=√1/2
x=+-1/√2
x = 1/√2. , x = -1/√2

Answer 2

Answer :

The equation is given to be : p(x) = 6x² - 3

To find the zeros of the given equation, Equate the given p(x) = 0

⇒ 6x² - 3 = 0

Dividing each term of the equation by 3

⇒ 2x² - 1 = 0

⇒ 2x² = 1

⇒ x² = 1/2

⇒ x = 1/2 and x = -1/2

⇒ α = 1/2 and β = -1/2

Now, α = 1/2

-b/a = -(-3)/6

⇒ -b/a = 1/2

So, α = -b/a

And, β = -1/2

So, β = b/a