Question

find the zeros of the quadratic polynomial is P of x is equal to a b x square + bracket open b square - 80 bracket close x minus b c and verify the relation between the zeros and the coefficient

Answer 1

$ab {x }^{2} + (b {}^{2} - ac)x - bc$

$abx {}^{2} + b {}^{2} x - acx - bc$

$bx(ax + b) - c(ax + b)$

$(bx - c)(ax + b)$

x = c / b and -b / a

Relation between zeroes and corfficient.

alpha = c / b and beta = -b / a



Thanks

Answer 2

Hope this helps you ☺