Question

Find the zeros of the quadratic polynomial x square + x -12 and verify the relationship between zeros and coefficient.

Answer 1

Answer:

Hey buddy, here is your solution:

$x^{2} +x-12$

$x^{2} +4x-3x-12$

$x(x+4)-3(x+4)$

$(x-3)(x+4)$

$Therefore,\\x-3=0\\x=3 \\and\\x+4=0\\x=-4$

The zeros are:

$\alpha =3\\and\\\\\beta =-4$

Verification of relationship between zeros and their coefficient:

$\alpha +\beta =-b/a\\3+(-4)=-(1)/1\\-1=-1$

$\alpha *\beta =c*a\\3*-4=-12/1\\-12=-12\\Hence, proved$

Hope it helps..........

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Answer 2

Answer:zeros are -4 and +3

Sum of the zeros are -1\1 and product of zeros are -12\1

Step-by-step explanation:

Given equation x square+ x-12 from -b+or - √b square-4ac divided by 2a the zeroes are -1+or-7\2 and -1+7\2 ,-1-7\2 and zeros are -4,+3. And sum of the zeros are (-4+3)=-1 and formula is -b\a therefore -1\1 . And product of the zeros are(-4×3)=-12 And formula is c\a=-12\1