Question

Find there consecutive integers whose sum is 27​

Answer 1

Let the consecutive numbers be ⇒ $\texttt {x, x+1 and x+2}$

Now our equation will be ⇒ $\texttt{x + x + 1 + x + 2 = 27}$

Let's solve your equation step-by-step.

$\texttt{x + x + 1 + x + 2 = 27}$

Step 1: Group Like Terms together.

$\texttt {(x + x + x) + (1 + 2) = 27}$

$\texttt{ 3x + 3 = 27}$

Step 2: Subtract 3 from both sides.

$\texttt{3x + 3 - 3 = 27 - 3}$

$\texttt{ 3x = 24}$

Step 3: Divide 3 from both sides.

$\sf { \frac{3x}{3} = \frac{24}{3} }$

$\texttt{x = 8}$

Now let's give 'x' it's value and find the consecutive numbers.

$\texttt{x = 8}$

$\texttt{x+1 = 8+1 = 9}$

$\texttt {x+2 = 8+2 = 10}$

∴The sum of 8, 9 and 10 gives us the sum of 27.

Answer 2

X+x+1+x+2=27
3x+3=27
3x=24
X=8
8+9+10=27