Question

Find thesmallestnumber by which 8640 must be divided so that the quotient is a perfect cube

Answer 1

Hey

Here is your answer,

8640 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3 x 5

5 occurs as a prime factor only one

Hence 5 is the smallest number by which 48640$ must be divided so that the quotient is a perfect cube.

Hope it helps you!

Answer 2

Answer:

Step-by-step explanation:

8640=2*2*2*2*2*2*3*3*3*5

2*2*2=8

2*2*2=8

3*3*3=27

5=5

5 is the smallest number by which 8640must be divided so that the quotient is a perfect cube