Question

find this guy's answer this question do not spam otherwise answer will be reported​

Answer 1

Step-by-step explanation:

sigma(5r²+4r-3)

=5×sigma(r²)+4×sigma(r)-3n

=5[n(n+1)(2n+1)/6]+4[n(n+1)/2]-3n

=(5n(n+1)(2n+1)+24n(n+1)-18n)/6

Answer 2

Answer:

Question ⤵

Sigma(5r²+4r-3)

$\huge\colorbox{yellow}{αηѕωєя࿐ ❤}$

Sigma(5r²+4r-3)

= 5×Sigma(r²)+4×Sigma(r)-3n

= 5[n(n+1)(2n+1)/6]+4[n(n+1)/2]-3n

= (5n(n+1)(2n+1)+24n(n+1)-18n)/6

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