Math, asked by avimaan69, 1 year ago

find thr area of an isosceles triangle whose petimeter is 30cm and each of equal sides is 12cm​

Answers

Answered by sahilarora33
0

Answer:

Step-by-step explanation:

we know that area of a triangle is sum of all sides

i.e a+b+c= 30 (given)

we have given to sides i.e  12 cm and 12 cm

so 12 +12+c=30

24+c=30

c=30-24

c=6 cm

semi perimeter of a triangle = a+b+c/2

= 12+12+6/2

=30/2

= 15

area of a triangle = under root s (s+a)(s+b)(s+c)

now put the value of a and b and c and u will get the area of the triangle

Answered by newton133
0

Answer:

1215cm²

Step-by-step explanation:

In an isosceles triangle two sides are equal

1st side=2nd side=12cm

3rd side=30-12-12=6cm

s=(a+b+c)/2=(12+12+6)/2=30/2=15

area =√15(15-12)(15-12)(15-6)

=15×3×3×9=1215cm²

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