Question

find three consecuitive no. such that the sum of first and second is 15 more than third​

Answer 1

Answer:

The three consecutive natural numbers are 16, 17 and 18.

Step-by-step explanation:

Let the 3 consecutive numbers be a, (a+1), and (a+2); where a is the first number, (a+1) is the second number, (a+2) is the third number.

The sum of the first and the second number = a + (a+1) = 2a+1

Given, the sum of the first and second is 15 more than the third no.

a + (a+1) = 15 + (a+2)

2a + 1 = 15 + a + 2

2a + 1 = 17 + a

2a – a = 17 -1  

a = 16

Hence, the 3 consecutive numbers are 16, 17 and 18.

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