Question

Find three consecutive even
integers whose sum is -48.

Answer 1

Answer:

let one no.be x,the other number be x+1 and the 3rd no be x+2

B/P

x+x+1+x+2=-48

》3x+3=-48

》3x=-48-3

》3x=-51

》x=-51/3

》x=-17

the nos.are -17,-18 and-19

Answer 2

Answer:

Let the nos be x,x+2,x+4

ATTQ

x+x+2+x+4=-48

3x+6=-48

3x=-48-6

3x=-54

$x = \frac{ - 54}{3}$

x=-18

The three consecutive even

integers whose sum is -48 are

-18

-18+2=-16

-18+4=-14

The nos are -18,-16 and -14