Question

Find three consecutive even natural
numbers such that seven times the
middle number is 42 less than four
times the sum of the other two.​

Answer 1

Answer:

Let x, x+1, x+2 be the three consecutive numbers.

Given that:

7(x+1) = 4(x+x+2)

7x + 7 = 8x + 8 -42

7 + 34 = x

x = 41

Therefore, the three consecutive even natural numbers are 41, 42, 43

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